Quote:
Originally Posted by acottawa
Setting aside the cost/etc. challenges, what sort of acceleration would you need to get speeds like that?
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Assuming constant acceleration to the mid point (and then constant deceleration at the same rate to the destination) as well as a straight path (not a good assumption), from Toronto to Ottawa (from the map on the CBC article):
d =225 km (half way)
t = 13.5 min (half the time)
since a = 2d/t^2 = 2 x 225 km / (13.5 min)^2 = 2.47 km/min^2 = 0.686 m/s^2 or about 0.07 G
In case you are curious, the top speed would be:
v = a t = 2.470 km/min^2 x 13.5 min = 33.3 km/min = 2000 km/h